Recessive - Revision history

WikiAdmin at 22:13, 25 February 2021

2021-02-25T22:13:23Z

WikiAdmin at 22:12, 25 February 2021

2021-02-25T22:12:56Z

WikiAdmin at 22:12, 25 February 2021

2021-02-25T22:12:41Z

WikiAdmin at 22:12, 25 February 2021

2021-02-25T22:12:08Z

WikiAdmin: Created page with "== Recessive == this is the initial pairing, f1. This shows the breakdown of "Het" Patternless x "Het" Patternless. This would be F2. A ge..."

2021-02-25T22:10:43Z

Created page with "== Recessive == thumb|right|this is the initial pairing, f1. This shows the breakdown of "Het" Patternless x "Het" Patternless. This would be F2. A ge..."

New page

== Recessive ==
[[File:Recessive.jpg|thumb|right|this is the initial pairing, f1.]]

This shows the breakdown of "Het" Patternless x "Het" Patternless. This would be F2.
A gene which is recessive only shows their effect if there are two copies of the gene in the pair of alleles from their parents. When using a Punnent Square, recessive traits are shown by using a lower case letter. An example of a recessive trait ([[Murphy Patternless]]) crossed with a Normal can be seen on the right.

When dealing with recessive traits, it takes two generations to show the trait. In our example, all of the F1, or First Generation babies will be heterozygous for the trait. To achieve a gecko who is homozygous for Murphy Patternless, the easiest route would be to breed the hatchlings to each other. There would be a 25% chance of creating a Murphy Patternless Leopard Gecko in the F2, or Second Generation. The other possibilities are 25% Normal, and 50% Normal heterozygous or het for Murphy Patternless.

Currently there are a few recessive traits in Leopard Geckos. They can be seen below:
* [[Tremper Albino]]
* [[Rainwater Albino]]
* [[Bell Albino]]
* [[Blizzard]]
* [[Murphy Patternless]]
* [[Eclipse]]
--MK Geckos 16:07, 18 September 2007 (EDT)

[[Category:Genetics]]

@@ Line 2: / Line 2: @@
 [[File:Recessive.jpg|right|this is the initial pairing, f1.]]
-[[File:Recessive het.jpg|thumb|This shows the breakdown of "Het" Patternless x "Het" Patternless. This would be F2.]]
+[[File:Recessive het.jpg|this shows the breakdown of "het" patternless x "het" patternless. this would be f2.]]
 A gene which is recessive only shows their effect if there are two copies of the gene in the pair of alleles from their parents. When using a Punnent Square, recessive traits are shown by using a lower case letter. An example of a recessive trait ([[Murphy Patternless]]) crossed with a Normal can be seen on the right.

← Older revision		Revision as of 22:12, 25 February 2021
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	[[File:Recessive.jpg\|thumb\|right\|this is the initial pairing, f1.]]		[[File:Recessive.jpg\|thumb\|right\|this is the initial pairing, f1.]]

		+	[[File:Recessive het.jpg\|thumb\|This shows the breakdown of "Het" Patternless x "Het" Patternless. This would be F2.]]

−	~~This shows the breakdown of "Het" Patternless x "Het" Patternless. This would be F2.~~
	A gene which is recessive only shows their effect if there are two copies of the gene in the pair of alleles from their parents. When using a Punnent Square, recessive traits are shown by using a lower case letter. An example of a recessive trait ([[Murphy Patternless]]) crossed with a Normal can be seen on the right.		A gene which is recessive only shows their effect if there are two copies of the gene in the pair of alleles from their parents. When using a Punnent Square, recessive traits are shown by using a lower case letter. An example of a recessive trait ([[Murphy Patternless]]) crossed with a Normal can be seen on the right.

← Older revision		Revision as of 22:12, 25 February 2021
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	When dealing with recessive traits, it takes two generations to show the trait. In our example, all of the F1, or First Generation babies will be heterozygous for the trait. To achieve a gecko who is homozygous for Murphy Patternless, the easiest route would be to breed the hatchlings to each other. There would be a 25% chance of creating a Murphy Patternless Leopard Gecko in the F2, or Second Generation. The other possibilities are 25% Normal, and 50% Normal heterozygous or het for Murphy Patternless.		When dealing with recessive traits, it takes two generations to show the trait. In our example, all of the F1, or First Generation babies will be heterozygous for the trait. To achieve a gecko who is homozygous for Murphy Patternless, the easiest route would be to breed the hatchlings to each other. There would be a 25% chance of creating a Murphy Patternless Leopard Gecko in the F2, or Second Generation. The other possibilities are 25% Normal, and 50% Normal heterozygous or het for Murphy Patternless.
		+

	Currently there are a few recessive traits in Leopard Geckos. They can be seen below:		Currently there are a few recessive traits in Leopard Geckos. They can be seen below:

@@ Line 1: / Line 1: @@
 == Recessive ==
-[[File:Recessive.jpg|thumb|right|this is the initial pairing, f1.]]
+[[File:Recessive.jpg|right|this is the initial pairing, f1.]]
 [[File:Recessive het.jpg|thumb|This shows the breakdown of "Het" Patternless x "Het" Patternless. This would be F2.]]
 A gene which is recessive only shows their effect if there are two copies of the gene in the pair of alleles from their parents. When using a Punnent Square, recessive traits are shown by using a lower case letter. An example of a recessive trait ([[Murphy Patternless]]) crossed with a Normal can be seen on the right.
 When dealing with recessive traits, it takes two generations to show the trait. In our example, all of the F1, or First Generation babies will be heterozygous for the trait. To achieve a gecko who is homozygous for Murphy Patternless, the easiest route would be to breed the hatchlings to each other. There would be a 25% chance of creating a Murphy Patternless Leopard Gecko in the F2, or Second Generation. The other possibilities are 25% Normal, and 50% Normal heterozygous or het for Murphy Patternless.